X^2-28x-48=0

Solution for X^2-28x-48=0 equation:

X^2-28X-48=0

a = 1; b = -28; c = -48;
Δ = b2-4ac
Δ = -282-4·1·(-48)
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{61}}{2*1}=\frac{28-4\sqrt{61}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{61}}{2*1}=\frac{28+4\sqrt{61}}{2}
$